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		<title>Number Theory: Lecture 24</title>
		<link>http://theoremoftheweek.wordpress.com/2011/11/30/number-theory-lecture-24/</link>
		<comments>http://theoremoftheweek.wordpress.com/2011/11/30/number-theory-lecture-24/#comments</comments>
		<pubDate>Wed, 30 Nov 2011 12:11:36 +0000</pubDate>
		<dc:creator>theoremoftheweek</dc:creator>
				<category><![CDATA[Cambridge Maths Tripos]]></category>
		<category><![CDATA[II Number Theory]]></category>
		<category><![CDATA[Lecture]]></category>

		<guid isPermaLink="false">http://theoremoftheweek.wordpress.com/?p=1392</guid>
		<description><![CDATA[In which we conclude our study of methods of factorising large numbers, and, indeed, the course. Lemma 76: Let be a convergent to .  Then , and moreover we have .  (The angle bracket notation is the same as that introduced in Lecture 7).  We proved this using our upper bound on , which in [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=theoremoftheweek.wordpress.com&amp;blog=8730266&amp;post=1392&amp;subd=theoremoftheweek&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p><em>In which we conclude our study of methods of factorising large numbers, and, indeed, the course.</em></p>
<p><span id="more-1392"></span></p>
<ul>
<li>Lemma 76: <em>Let <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7Bp_n%7D%7Bq_n%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;frac{p_n}{q_n}' title='&#92;frac{p_n}{q_n}' class='latex' /> be a convergent to <img src='http://s0.wp.com/latex.php?latex=%5Csqrt%7BN%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;sqrt{N}' title='&#92;sqrt{N}' class='latex' />.  Then <img src='http://s0.wp.com/latex.php?latex=%5Clangle+p_n%5E2+%5Crangle+%3D+p_n%5E2+-+q_n%5E2+N&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;langle p_n^2 &#92;rangle = p_n^2 - q_n^2 N' title='&#92;langle p_n^2 &#92;rangle = p_n^2 - q_n^2 N' class='latex' />, and moreover we have <img src='http://s0.wp.com/latex.php?latex=%7C%5Clangle+p_n%5E2+%5Crangle%7C+%5Cleq+2+%5Csqrt%7BN%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='|&#92;langle p_n^2 &#92;rangle| &#92;leq 2 &#92;sqrt{N}' title='|&#92;langle p_n^2 &#92;rangle| &#92;leq 2 &#92;sqrt{N}' class='latex' />.</em>  (The angle bracket notation is the same as that introduced in <a title="Number Theory Lecture 7" href="http://theoremoftheweek.wordpress.com/2011/10/21/number-theory-lecture-7/">Lecture 7</a>).  We proved this using our upper bound on <img src='http://s0.wp.com/latex.php?latex=%7Cp_n+-+q_n+%5Csqrt%7BN%7D%7C&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='|p_n - q_n &#92;sqrt{N}|' title='|p_n - q_n &#92;sqrt{N}|' class='latex' />, which in turn we proved in <a title="Number Theory Lecture 19" href="http://theoremoftheweek.wordpress.com/2011/11/18/number-theory-lecture-19/">Lecture 19</a>.</li>
<li>Description of the <em>continued-fraction method</em>, which is really a variant of the factor-base method that we saw <a title="Number Theory Lecture 23" href="http://theoremoftheweek.wordpress.com/2011/11/28/number-theory-lecture-23/">last time</a>, using Lemma 76 as a crucial ingredient.</li>
<li>Description of <em>Pollard&#8217;s <img src='http://s0.wp.com/latex.php?latex=p-1&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='p-1' title='p-1' class='latex' /> method</em>.</li>
</ul>
<h4>Further reading</h4>
<p>Koblitz (<em>A Course in Number Theory and Cryptography</em>) and Davenport (<em>The Higher Arithmetic</em>) both discuss these methods, together with other variants.  Right at the end, I mentioned Shor&#8217;s algorithm for factorisation using a quantum computer; Scott Aaronson has written a lovely non-technical description on <a title="Scott Aaronson's blog post on Shor's algorithm" href="http://www.scottaaronson.com/blog/?p=208">his blog</a>, and he includes links to a number of sources of more information.</p>
<p>I hope that some of you may be inspired to read in more depth about the ideas of this course, and about other aspects of number theory.  Of course, there are many number theory books and many websites where you can do this, so I shan&#8217;t try to list them (but please do share your favourites in the comments below).</p>
<p>I&#8217;ll just mention one book, <a title="The Princeton Companion to Mathematics" href="http://press.princeton.edu/titles/8350.html"><em>The Princeton Companion to Mathematics</em></a>, edited by Tim Gowers (with associate editors June Barrow-Green and Imre Leader).  This has short sections on various important concepts in pure mathematics, including several from number theory (such as elliptic curves, the Euclidean algorithm and continued fractions, the ideal class group, L-functions, modular arithmetic, number fields, the Riemann zeta function and many more).  Perhaps even more interestingly, it has slightly longer articles (10&#8211;20 pages) on branches of mathematics, written by leading mathematicians in those areas.  So there&#8217;s &#8220;Algebraic Numbers&#8221; by Barry Mazur, &#8220;Analytic Number Theory&#8221; by Andrew Granville, &#8220;Computational Number Theory&#8221; by Carl Pomerance, &#8220;Arithmetic Geometry&#8221; by Jordan S. Ellenberg, and many more (they aren&#8217;t all about number theory!).  And then there are short pieces about particular theorems and problems, such as the ABC conjecture, the Birch&#8211;Swinnerton-Dyer conjecture, Fermat&#8217;s last theorem, the Prime Number Theorem and the Riemann Hypothesis, Problems and Results in Additive Number Theory, and so on.  If you want a broader picture of mathematics and how the ideas from your various lecture courses are used, and if you want to know what current research mathematicians in the area are thinking about, this would be a great place to start reading.  Perhaps your college library has a copy?</p>
<h4>Preparation for Lectu&#8230; oh, this is the end of the course!</h4>
<p>I plan to write about some of the topics from this course in more detail over the next few months (in the style of the `Theorem&#8217; posts on this blog), so you might want to keep an eye out for them.  And of course the comment facility is still there for asking questions.  I hope that this course has inspired you to find out more about Number Theory!</p>
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		<item>
		<title>Number Theory: Lecture 23</title>
		<link>http://theoremoftheweek.wordpress.com/2011/11/28/number-theory-lecture-23/</link>
		<comments>http://theoremoftheweek.wordpress.com/2011/11/28/number-theory-lecture-23/#comments</comments>
		<pubDate>Mon, 28 Nov 2011 12:07:43 +0000</pubDate>
		<dc:creator>theoremoftheweek</dc:creator>
				<category><![CDATA[Cambridge Maths Tripos]]></category>
		<category><![CDATA[II Number Theory]]></category>
		<category><![CDATA[Lecture]]></category>

		<guid isPermaLink="false">http://theoremoftheweek.wordpress.com/?p=1388</guid>
		<description><![CDATA[In which we encounter some methods for factorising a large number. Description of Fermat factorisation. Definition of least absolute residue.  (See also Gauss&#8217;s lemma, in lecture 7.) Definition of a factor base and of a -number. Description of the factor-base method. Further reading Koblitz (A Course in Number Theory and Cryptography) and recent editions of [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=theoremoftheweek.wordpress.com&amp;blog=8730266&amp;post=1388&amp;subd=theoremoftheweek&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p><em>In which we encounter some methods for factorising a large number.</em></p>
<p><span id="more-1388"></span></p>
<ul>
<li>Description of <em>Fermat factorisation</em>.</li>
<li>Definition of <em>least absolute residue</em>.  (See also Gauss&#8217;s lemma, in <a title="Number Theory Lecture 7" href="https://theoremoftheweek.wordpress.com/2011/10/21/number-theory-lecture-7/">lecture 7</a>.)</li>
<li>Definition of a <em>factor base</em> and of a <em><img src='http://s0.wp.com/latex.php?latex=B&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='B' title='B' class='latex' />-number</em>.</li>
<li>Description of the <em>factor-base method</em>.</li>
</ul>
<h4>Further reading</h4>
<p>Koblitz (<em>A Course in Number Theory and Cryptography</em>) and recent editions of Davenport (<em>The Higher Arithmetic</em>) both cover this material nicely.</p>
<h4>Preparation for Lecture 24</h4>
<p>As we saw, the factor-base method relies on coming up with a suitable factor base <img src='http://s0.wp.com/latex.php?latex=B&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='B' title='B' class='latex' /> and suitable <img src='http://s0.wp.com/latex.php?latex=B&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='B' title='B' class='latex' />-numbers.  How could continued fractions help us with this?</p>
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		<title>Number Theory: Lecture 22</title>
		<link>http://theoremoftheweek.wordpress.com/2011/11/25/number-theory-lecture-22/</link>
		<comments>http://theoremoftheweek.wordpress.com/2011/11/25/number-theory-lecture-22/#comments</comments>
		<pubDate>Fri, 25 Nov 2011 12:25:38 +0000</pubDate>
		<dc:creator>theoremoftheweek</dc:creator>
				<category><![CDATA[Cambridge Maths Tripos]]></category>
		<category><![CDATA[II Number Theory]]></category>
		<category><![CDATA[Lecture]]></category>

		<guid isPermaLink="false">http://theoremoftheweek.wordpress.com/?p=1378</guid>
		<description><![CDATA[In which we continue our examination of various sorts of pseudoprime. Lemma 72: If is not an Euler pseudoprime to some base , then for at least half of all bases we find that is not an Euler pseudoprime.  This was analogous to Proposition 71 last time, and the proof was almost identical. Proposition 73: [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=theoremoftheweek.wordpress.com&amp;blog=8730266&amp;post=1378&amp;subd=theoremoftheweek&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p><em>In which we continue our examination of various sorts of pseudoprime.</em></p>
<p><span id="more-1378"></span></p>
<ul>
<li>Lemma 72: <em>If <img src='http://s0.wp.com/latex.php?latex=n&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='n' title='n' class='latex' /> is not an Euler pseudoprime to some base <img src='http://s0.wp.com/latex.php?latex=b&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='b' title='b' class='latex' />, then for at least half of all bases we find that <img src='http://s0.wp.com/latex.php?latex=n&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='n' title='n' class='latex' /> is not an Euler pseudoprime.</em>  This was analogous to <a title="Number Theory Lecture 21" href="http://theoremoftheweek.wordpress.com/2011/11/23/number-theory-lecture-21/">Proposition 71</a> last time, and the proof was almost identical.</li>
<li>Proposition 73: <em>Let <img src='http://s0.wp.com/latex.php?latex=n&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='n' title='n' class='latex' /> be an odd composite natural number.  Then <img src='http://s0.wp.com/latex.php?latex=n&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='n' title='n' class='latex' /> is an Euler pseudoprime to at most half of all bases.</em>  (So there are not numbers analogous to Carmichael numbers.)  We showed that there is some base <img src='http://s0.wp.com/latex.php?latex=b&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='b' title='b' class='latex' /> to which <img src='http://s0.wp.com/latex.php?latex=n&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='n' title='n' class='latex' /> is not an Euler pseudoprime, and then used Lemma 72.  We split into two cases, depending on whether <img src='http://s0.wp.com/latex.php?latex=n&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='n' title='n' class='latex' /> is divisible by the square of a prime or not.</li>
<li>Description of the <em>Solovay-Strassen primality test</em>, a probabilistic primality test that relies on Proposition 73 for its usefulness.</li>
<li>Definition of a <em>strong pseudoprime to the base <img src='http://s0.wp.com/latex.php?latex=b&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='b' title='b' class='latex' /></em>.</li>
<li>Proposition 74: <em>Let <img src='http://s0.wp.com/latex.php?latex=n&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='n' title='n' class='latex' /> be an odd composite natural number.  If <img src='http://s0.wp.com/latex.php?latex=n&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='n' title='n' class='latex' /> is a strong pseudoprime to the base <img src='http://s0.wp.com/latex.php?latex=b&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='b' title='b' class='latex' />, then it is also an Euler pseudoprime to the base <img src='http://s0.wp.com/latex.php?latex=b&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='b' title='b' class='latex' />.</em>  We did not prove this in the lecture.</li>
<li>Theorem 75: <em>If <img src='http://s0.wp.com/latex.php?latex=n&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='n' title='n' class='latex' /> is an odd composite natural number, then <img src='http://s0.wp.com/latex.php?latex=n&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='n' title='n' class='latex' /> is a strong pseudoprime to the base <img src='http://s0.wp.com/latex.php?latex=b&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='b' title='b' class='latex' /> for at most one quarter of all possible bases.</em>  We did not prove this either.</li>
<li>Description of the <em>Miller-Rabin primality test</em>, another probabilistic primality test.</li>
<li>We mentioned the <em>Agrawal-Kayal-Saxena primality test</em>, without going into any details.  See below for a reference.</li>
</ul>
<p>I gave out the fourth (and final) examples sheet, which is now also available on the <a title="Number Theory course page" href="http://www.dpmms.cam.ac.uk/~vrn20/NumberTheory2011.html">course page</a>.  Here are a couple of comments on that examples sheet.</p>
<p>Q5(ii).  You are, of course, supposed to incorporate the condition from part (i) into this statement.  I omitted it to avoid making the question even longer, but this seems to have caused some confusion.  My apologies to those of you who were unclear about this.</p>
<p>Q15.  There is no harm in trying the question as written on the sheet, but I meant to put <img src='http://s0.wp.com/latex.php?latex=N+%3D+53467&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='N = 53467' title='N = 53467' class='latex' /> &#8212; the question is more interesting that way!</p>
<h4>Further reading</h4>
<p>Koblitz (<em>A Course in Number Theory and Cryptography</em>) and Davenport (<em>The Higher Arithmetic</em>) both have material on pseudoprimes and primality testing.  Terry Tao has a <a title="Terry Tao blog post on the AKS primality test" href="http://terrytao.wordpress.com/2009/08/11/the-aks-primality-test/">blog post</a> about the AKS primality test, with various links to further reading.</p>
<h4>Preparation for Lecture 23</h4>
<p>Next time we&#8217;ll be thinking about factorisation.  Given a large integer <img src='http://s0.wp.com/latex.php?latex=N&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='N' title='N' class='latex' />, we&#8217;d like to find a non-trivial factor.  Why might it help to find two squares that are congruent modulo <img src='http://s0.wp.com/latex.php?latex=N&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='N' title='N' class='latex' />: that is, <img src='http://s0.wp.com/latex.php?latex=r&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='r' title='r' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=s&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='s' title='s' class='latex' /> such that <img src='http://s0.wp.com/latex.php?latex=r%5E2+%5Cequiv+s%5E2+%5Cpmod%7BN%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='r^2 &#92;equiv s^2 &#92;pmod{N}' title='r^2 &#92;equiv s^2 &#92;pmod{N}' class='latex' />?  And can we always find such squares?</p>
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		<title>Number Theory: Lecture 21</title>
		<link>http://theoremoftheweek.wordpress.com/2011/11/23/number-theory-lecture-21/</link>
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		<pubDate>Wed, 23 Nov 2011 12:20:55 +0000</pubDate>
		<dc:creator>theoremoftheweek</dc:creator>
				<category><![CDATA[Cambridge Maths Tripos]]></category>
		<category><![CDATA[II Number Theory]]></category>
		<category><![CDATA[Lecture]]></category>

		<guid isPermaLink="false">http://theoremoftheweek.wordpress.com/?p=1368</guid>
		<description><![CDATA[In which we learn a little more about solutions to Pell&#8217;s equation, and start thinking about primality testing. Lemma 69: If and are solutions to , then so is .  This was a straightforward check (and we managed to avoid doing lots of algebra).  So there are infinitely many solutions to Pell&#8217;s equation (since we [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=theoremoftheweek.wordpress.com&amp;blog=8730266&amp;post=1368&amp;subd=theoremoftheweek&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p><em>In which we learn a little more about solutions to Pell&#8217;s equation, and start thinking about primality testing.</em></p>
<p><span id="more-1368"></span></p>
<ul>
<li>Lemma 69: <em>If <img src='http://s0.wp.com/latex.php?latex=%28x_1%2C+y_1%29&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='(x_1, y_1)' title='(x_1, y_1)' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=%28x_2%2C+y_2%29&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='(x_2, y_2)' title='(x_2, y_2)' class='latex' /> are solutions to <img src='http://s0.wp.com/latex.php?latex=x%5E2+-+Ny%5E2+%3D+1&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='x^2 - Ny^2 = 1' title='x^2 - Ny^2 = 1' class='latex' />, then so is <img src='http://s0.wp.com/latex.php?latex=%28x_1+x_2+%2B+y_1+y_2+N%2C+x_1+y_2+%2B+x_2+y_1%29&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='(x_1 x_2 + y_1 y_2 N, x_1 y_2 + x_2 y_1)' title='(x_1 x_2 + y_1 y_2 N, x_1 y_2 + x_2 y_1)' class='latex' />.</em>  This was a straightforward check (and we managed to avoid doing lots of algebra).  So there are infinitely many solutions to Pell&#8217;s equation (since we already know that there is one).</li>
<li>Definition of a <em>pseudoprime to the base <img src='http://s0.wp.com/latex.php?latex=b&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='b' title='b' class='latex' />.</em></li>
<li>Lemma 70: If <img src='http://s0.wp.com/latex.php?latex=n&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='n' title='n' class='latex' /> is pseudoprime to the bases <img src='http://s0.wp.com/latex.php?latex=b_1&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='b_1' title='b_1' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=b_2&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='b_2' title='b_2' class='latex' />, then <img src='http://s0.wp.com/latex.php?latex=n&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='n' title='n' class='latex' /> is pseudoprime to the base <img src='http://s0.wp.com/latex.php?latex=b_1+b_2&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='b_1 b_2' title='b_1 b_2' class='latex' /> and also to the base <img src='http://s0.wp.com/latex.php?latex=b_1+b_2%5E%7B-1%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='b_1 b_2^{-1}' title='b_1 b_2^{-1}' class='latex' />.  This was easy to check.</li>
<li>Proposition 71: <em>If <img src='http://s0.wp.com/latex.php?latex=n&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='n' title='n' class='latex' /> is not pseudoprime to some base <img src='http://s0.wp.com/latex.php?latex=b&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='b' title='b' class='latex' />, then at least half of all bases are such that <img src='http://s0.wp.com/latex.php?latex=n&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='n' title='n' class='latex' /> is not pseudoprime to those bases.</em>  We showed that there is an injection from {bases to which <img src='http://s0.wp.com/latex.php?latex=n&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='n' title='n' class='latex' /> is pseudoprime} to {bases to which <img src='http://s0.wp.com/latex.php?latex=n&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='n' title='n' class='latex' /> is not pseudoprime}.</li>
<li>Definition of a <em>Carmichael number</em>.</li>
<li>Definition of an <em>Euler pseudoprime to the base <img src='http://s0.wp.com/latex.php?latex=b&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='b' title='b' class='latex' />.</em></li>
</ul>
<h4>Further reading</h4>
<p>Baker (<em>A concise introduction to the theory of numbers</em>) and Davenport (<em>The Higher Arithmetic</em>) both discuss Pell&#8217;s equation and the link with continued fractions.  Koblitz (<em>A Course in Number Theory and Cryptography</em>) has a good section on primality testing and pseudoprimes.  I mentioned the paper of <a title="Alford, Granville and Pomerance paper" href="http://www.dms.umontreal.ca/%7Eandrew/PDF/carmichael.pdf">Alford, Granville and Pomerance</a> that shows that there are infinitely many Carmichael numbers.</p>
<h4>Preparation for Lecture 22</h4>
<p>We finished with the definition of Euler pseudoprimes.  It would be helpful to look back over our work today on Fermat pseudoprimes, to see whether you can adapt it to Euler pseudoprimes.  I suggest that you start with some examples.  Are there analogues of Proposition 71 and of Carmichael numbers for Euler pseudoprimes?  You could also think about Carmichael numbers: can you find any?  If <img src='http://s0.wp.com/latex.php?latex=n&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='n' title='n' class='latex' /> is a Carmichael number, what can you say about <img src='http://s0.wp.com/latex.php?latex=n&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='n' title='n' class='latex' /> and its prime factors?</p>
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		<title>Number Theory: Lecture 20</title>
		<link>http://theoremoftheweek.wordpress.com/2011/11/21/number-theory-lecture-20/</link>
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		<pubDate>Mon, 21 Nov 2011 12:10:04 +0000</pubDate>
		<dc:creator>theoremoftheweek</dc:creator>
				<category><![CDATA[Cambridge Maths Tripos]]></category>
		<category><![CDATA[II Number Theory]]></category>
		<category><![CDATA[Lecture]]></category>

		<guid isPermaLink="false">http://theoremoftheweek.wordpress.com/?p=1067</guid>
		<description><![CDATA[In which we find a link between continued fractions and Pell&#8217;s equation. Theorem 63: Let be a natural number, and let have convergents .  If and are integers with , then .  (So .)  The key idea of the proof was to find a way to link and (about which we know very little) with [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=theoremoftheweek.wordpress.com&amp;blog=8730266&amp;post=1067&amp;subd=theoremoftheweek&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p><em>In which we find a link between continued fractions and Pell&#8217;s equation.</em></p>
<p><span id="more-1067"></span></p>
<ul>
<li><a title="Theorem 35: the best rational approximations come from continued fractions" href="http://theoremoftheweek.wordpress.com/2010/09/08/theorem-35-the-best-rational-approximations-come-from-continued-fractions/">Theorem 63</a>: <em>Let <img src='http://s0.wp.com/latex.php?latex=n&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='n' title='n' class='latex' /> be a natural number, and let <img src='http://s0.wp.com/latex.php?latex=%5Ctheta&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;theta' title='&#92;theta' class='latex' /> have convergents <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7Bp_k%7D%7Bq_k%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;frac{p_k}{q_k}' title='&#92;frac{p_k}{q_k}' class='latex' />.  If <img src='http://s0.wp.com/latex.php?latex=p&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='p' title='p' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=q&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='q' title='q' class='latex' /> are integers with <img src='http://s0.wp.com/latex.php?latex=0+%3C+q+%3C+q_n&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='0 &lt; q &lt; q_n' title='0 &lt; q &lt; q_n' class='latex' />, then <img src='http://s0.wp.com/latex.php?latex=%7Cq+%5Ctheta+-+p%7C+%5Cgeq+%7Cq_%7Bn-1%7D+%5Ctheta+-+p_%7Bn-1%7D%7C&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='|q &#92;theta - p| &#92;geq |q_{n-1} &#92;theta - p_{n-1}|' title='|q &#92;theta - p| &#92;geq |q_{n-1} &#92;theta - p_{n-1}|' class='latex' />.  </em>(So <img src='http://s0.wp.com/latex.php?latex=%7Cq%5Ctheta+-+p%7C+%5Cgeq+%7C+q_n+%5Ctheta+-+p_n%7C&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='|q&#92;theta - p| &#92;geq | q_n &#92;theta - p_n|' title='|q&#92;theta - p| &#92;geq | q_n &#92;theta - p_n|' class='latex' />.)  <em></em> The key idea of the proof was to find a way to link <img src='http://s0.wp.com/latex.php?latex=p&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='p' title='p' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=q&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='q' title='q' class='latex' /> (about which we know very little) with <img src='http://s0.wp.com/latex.php?latex=p_%7Bn-1%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='p_{n-1}' title='p_{n-1}' class='latex' />, <img src='http://s0.wp.com/latex.php?latex=q_%7Bn-1%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='q_{n-1}' title='q_{n-1}' class='latex' />, <img src='http://s0.wp.com/latex.php?latex=p_n&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='p_n' title='p_n' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=q_n&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='q_n' title='q_n' class='latex' /> (about which we know quite a lot).  We were able to do this by finding integers <img src='http://s0.wp.com/latex.php?latex=u&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='u' title='u' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=v&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='v' title='v' class='latex' /> such that <img src='http://s0.wp.com/latex.php?latex=p+%3D+u+p_%7Bn-1%7D+%2B+v+p_n&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='p = u p_{n-1} + v p_n' title='p = u p_{n-1} + v p_n' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=q+%3D+u+q_%7Bn-1%7D+%2B+v+q_n&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='q = u q_{n-1} + v q_n' title='q = u q_{n-1} + v q_n' class='latex' />.  By thinking about the signs of <img src='http://s0.wp.com/latex.php?latex=u&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='u' title='u' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=v&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='v' title='v' class='latex' /> (which must be different), we were able to obtain a lower bound for <img src='http://s0.wp.com/latex.php?latex=%7Cq+%5Ctheta+-+p%7C&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='|q &#92;theta - p|' title='|q &#92;theta - p|' class='latex' />.</li>
<li>Corollary 64: <em>If <img src='http://s0.wp.com/latex.php?latex=p&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='p' title='p' class='latex' /> is an integer and <img src='http://s0.wp.com/latex.php?latex=q&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='q' title='q' class='latex' /> is a natural number with <img src='http://s0.wp.com/latex.php?latex=%7C%5Ctheta+-+%5Cfrac%7Bp%7D%7Bq%7D%7C+%3C+%5Cfrac%7B1%7D%7B2q%5E2%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='|&#92;theta - &#92;frac{p}{q}| &lt; &#92;frac{1}{2q^2}' title='|&#92;theta - &#92;frac{p}{q}| &lt; &#92;frac{1}{2q^2}' class='latex' />, then <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7Bp%7D%7Bq%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;frac{p}{q}' title='&#92;frac{p}{q}' class='latex' /> is a convergent for <img src='http://s0.wp.com/latex.php?latex=%5Ctheta&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;theta' title='&#92;theta' class='latex' />.</em>  This is one of those proofs that becomes easier if you try to prove something slightly stronger.  We showed that if <img src='http://s0.wp.com/latex.php?latex=q_n+%5Cleq+q+%3C+q_%7Bn%2B1%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='q_n &#92;leq q &lt; q_{n+1}' title='q_n &#92;leq q &lt; q_{n+1}' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=%7C+%5Ctheta+-+%5Cfrac%7Bp%7D%7Bq%7D%7C+%3C+%5Cfrac%7B1%7D%7B2q%5E2%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='| &#92;theta - &#92;frac{p}{q}| &lt; &#92;frac{1}{2q^2}' title='| &#92;theta - &#92;frac{p}{q}| &lt; &#92;frac{1}{2q^2}' class='latex' />, then <img src='http://s0.wp.com/latex.php?latex=%7C+%5Cfrac%7Bp%7D%7Bq%7D+-+%5Cfrac%7Bp_n%7D%7Bq_n%7D%7C+%3C+%5Cfrac%7B1%7D%7Bq+q_n%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='| &#92;frac{p}{q} - &#92;frac{p_n}{q_n}| &lt; &#92;frac{1}{q q_n}' title='| &#92;frac{p}{q} - &#92;frac{p_n}{q_n}| &lt; &#92;frac{1}{q q_n}' class='latex' />, and so <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7Bp%7D%7Bq%7D+%3D+%5Cfrac%7Bp_n%7D%7Bq_n%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;frac{p}{q} = &#92;frac{p_n}{q_n}' title='&#92;frac{p}{q} = &#92;frac{p_n}{q_n}' class='latex' />.</li>
<li>Definition of <em>Pell&#8217;s equation</em> <img src='http://s0.wp.com/latex.php?latex=x%5E2+-+Ny%5E2+%3D+1&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='x^2 - Ny^2 = 1' title='x^2 - Ny^2 = 1' class='latex' /> (where <img src='http://s0.wp.com/latex.php?latex=N&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='N' title='N' class='latex' /> is a fixed natural number that is not a square, and we are interested in integer solutions for <img src='http://s0.wp.com/latex.php?latex=x&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='x' title='x' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=y&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='y' title='y' class='latex' />).</li>
<li>Corollary 65: <em>Let <img src='http://s0.wp.com/latex.php?latex=N&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='N' title='N' class='latex' /> be a natural number that is not a square.  If <img src='http://s0.wp.com/latex.php?latex=x&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='x' title='x' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=y&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='y' title='y' class='latex' /> are positive integers satisfying Pell&#8217;s equation <img src='http://s0.wp.com/latex.php?latex=x%5E2+-+Ny%5E2+%3D+1&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='x^2 - Ny^2 = 1' title='x^2 - Ny^2 = 1' class='latex' />, then <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7Bx%7D%7By%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;frac{x}{y}' title='&#92;frac{x}{y}' class='latex' /> is a convergent for <img src='http://s0.wp.com/latex.php?latex=%5Csqrt%7BN%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;sqrt{N}' title='&#92;sqrt{N}' class='latex' />.</em>  This follows nicely from the previous result.</li>
<li>Theorem 66 (Lagrange): <em>The continued fraction of <img src='http://s0.wp.com/latex.php?latex=%5Ctheta&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;theta' title='&#92;theta' class='latex' /> is eventually periodic if and only if <img src='http://s0.wp.com/latex.php?latex=%5Ctheta&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;theta' title='&#92;theta' class='latex' /> is a quadratic irrational.</em>  We did not prove this in the lecture, but saw an outline of some of the ideas of the proof.</li>
<li>Theorem 67: <em>Let <img src='http://s0.wp.com/latex.php?latex=N&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='N' title='N' class='latex' /> be a natural number that is not a square.  Then <img src='http://s0.wp.com/latex.php?latex=%5Csqrt%7BN%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;sqrt{N}' title='&#92;sqrt{N}' class='latex' /> has a continued fraction of the form <img src='http://s0.wp.com/latex.php?latex=%5Ba_0%3B+%5Coverline%7Ba_1%2C+a_2%2C+%5Cdotsc%2C+a_2%2C+a_1%2C+2a_0%7D%5D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='[a_0; &#92;overline{a_1, a_2, &#92;dotsc, a_2, a_1, 2a_0}]' title='[a_0; &#92;overline{a_1, a_2, &#92;dotsc, a_2, a_1, 2a_0}]' class='latex' />.</em>  We did not prove this either.</li>
<li>Proposition 68: <em>Let <img src='http://s0.wp.com/latex.php?latex=N&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='N' title='N' class='latex' /> be a natural number that is not a square.  Then there are integers <img src='http://s0.wp.com/latex.php?latex=x&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='x' title='x' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=y&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='y' title='y' class='latex' /> such that <img src='http://s0.wp.com/latex.php?latex=x%5E2+-+Ny%5E2+%3D+1&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='x^2 - Ny^2 = 1' title='x^2 - Ny^2 = 1' class='latex' />.</em>  We showed that there is a convergent <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7Bp_n%7D%7Bq_n%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;frac{p_n}{q_n}' title='&#92;frac{p_n}{q_n}' class='latex' /> for <img src='http://s0.wp.com/latex.php?latex=%5Csqrt%7BN%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;sqrt{N}' title='&#92;sqrt{N}' class='latex' /> such that <img src='http://s0.wp.com/latex.php?latex=p_n%5E2+-+N+q_n%5E2+%3D+1&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='p_n^2 - N q_n^2 = 1' title='p_n^2 - N q_n^2 = 1' class='latex' />, namely the convergent at the end of either the first or second period.</li>
</ul>
<h4>Further reading</h4>
<p>Davenport (<em>The Higher Arithmetic</em>), Baker (<em>A concise introduction to the theory of numbers</em>) and Hardy and Wright (<em>An Introduction to the Theory of Numbers</em>) all cover this material on continued fractions and Pell&#8217;s equation.</p>
<p>There&#8217;s also some nice material related to this on NRICH, based on Conway&#8217;s tangles.  There&#8217;s an <a title="NRICH article on tangles" href="http://nrich.maths.org/5681">article</a> by Mike Pearson, which starts by mentioning two NRICH problems; I encourage you to try those problems before reading Mike&#8217;s article.</p>
<h4>Preparation for Lecture 21</h4>
<p>Next time we&#8217;ll be thinking about primality testing.  That is, given a large number we wish to check (rapidly!) whether it is prime.  In this course so far we&#8217;ve seen a few results of the form &#8220;If <img src='http://s0.wp.com/latex.php?latex=p&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='p' title='p' class='latex' /> is prime, then &#8230;&#8221;, for example <a title="Number Theory Lecture 2" href="http://theoremoftheweek.wordpress.com/2011/10/10/number-theory-lecture-2/">Fermat&#8217;s Little Theorem</a> and <a title="Number Theory Lecture 6" href="http://theoremoftheweek.wordpress.com/2011/10/19/number-theory-lecture-6/">Euler&#8217;s criterion</a>.  It would be helpful to go back to those two results in particular, to think about whether the result could hold if <img src='http://s0.wp.com/latex.php?latex=p&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='p' title='p' class='latex' /> is <em>not</em> prime.  Does either result give us a useful primality test?</p>
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		<title>Number Theory: Lecture 19</title>
		<link>http://theoremoftheweek.wordpress.com/2011/11/18/number-theory-lecture-19/</link>
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		<pubDate>Fri, 18 Nov 2011 12:04:53 +0000</pubDate>
		<dc:creator>theoremoftheweek</dc:creator>
				<category><![CDATA[Cambridge Maths Tripos]]></category>
		<category><![CDATA[II Number Theory]]></category>
		<category><![CDATA[Lecture]]></category>

		<guid isPermaLink="false">http://theoremoftheweek.wordpress.com/?p=1061</guid>
		<description><![CDATA[In which we explore infinite continued fractions. Definition of convergents. Definition of sequences and . Lemma 58: For , we have .  That is, is equal to the convergent.  We proved this by induction, using the fact that . Lemma 59: For , we have .  This was an easy induction. Lemma 60: For , [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=theoremoftheweek.wordpress.com&amp;blog=8730266&amp;post=1061&amp;subd=theoremoftheweek&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p><em>In which we explore infinite continued fractions.</em></p>
<p><span id="more-1061"></span></p>
<ul>
<li>Definition of <em></em><em>convergents</em>.</li>
<li>Definition of sequences <img src='http://s0.wp.com/latex.php?latex=p_n&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='p_n' title='p_n' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=q_n&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='q_n' title='q_n' class='latex' />.</li>
<li>Lemma 58: <em>For <img src='http://s0.wp.com/latex.php?latex=n+%5Cgeq+0&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='n &#92;geq 0' title='n &#92;geq 0' class='latex' />, we have <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7Bp_n%7D%7Bq_n%7D+%3D+%5Ba_0%2C+a_1%2C+%5Cdotsc%2C+a_n%5D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;frac{p_n}{q_n} = [a_0, a_1, &#92;dotsc, a_n]' title='&#92;frac{p_n}{q_n} = [a_0, a_1, &#92;dotsc, a_n]' class='latex' />.  That is, <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7Bp_n%7D%7Bq_n%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;frac{p_n}{q_n}' title='&#92;frac{p_n}{q_n}' class='latex' /> is equal to the <img src='http://s0.wp.com/latex.php?latex=n%5E%7B%5Ctextrm%7Bth%7D%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='n^{&#92;textrm{th}}' title='n^{&#92;textrm{th}}' class='latex' /> convergent.</em>  We proved this by induction, using the fact that <img src='http://s0.wp.com/latex.php?latex=%5Ba_0%2C+a_1%2C+%5Cdotsc%2C+a_n%2C+a_%7Bn%2B1%7D%5D+%3D+%5Ba_0%2C+a_1%2C+%5Cdotsc%2C+a_n+%2B+%5Cfrac%7B1%7D%7Ba_%7Bn%2B1%7D%7D%5D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='[a_0, a_1, &#92;dotsc, a_n, a_{n+1}] = [a_0, a_1, &#92;dotsc, a_n + &#92;frac{1}{a_{n+1}}]' title='[a_0, a_1, &#92;dotsc, a_n, a_{n+1}] = [a_0, a_1, &#92;dotsc, a_n + &#92;frac{1}{a_{n+1}}]' class='latex' />.</li>
<li>Lemma 59: <em>For <img src='http://s0.wp.com/latex.php?latex=n+%5Cgeq+1&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='n &#92;geq 1' title='n &#92;geq 1' class='latex' />, we have <img src='http://s0.wp.com/latex.php?latex=p_n+q_%7Bn-1%7D+-+p_%7Bn-1%7D+q_n+%3D+%28-1%29%5E%7Bn%2B1%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='p_n q_{n-1} - p_{n-1} q_n = (-1)^{n+1}' title='p_n q_{n-1} - p_{n-1} q_n = (-1)^{n+1}' class='latex' />.</em>  This was an easy induction.</li>
<li>Lemma 60: <em>For <img src='http://s0.wp.com/latex.php?latex=n+%5Cgeq+0&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='n &#92;geq 0' title='n &#92;geq 0' class='latex' />, if <img src='http://s0.wp.com/latex.php?latex=a_0&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='a_0' title='a_0' class='latex' />, <img src='http://s0.wp.com/latex.php?latex=a_1&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='a_1' title='a_1' class='latex' />, <img src='http://s0.wp.com/latex.php?latex=a_2&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='a_2' title='a_2' class='latex' />, &#8230;, <img src='http://s0.wp.com/latex.php?latex=a_n&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='a_n' title='a_n' class='latex' /> are integers, then the terms <img src='http://s0.wp.com/latex.php?latex=p_n&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='p_n' title='p_n' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=q_n&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='q_n' title='q_n' class='latex' /> are coprime integers.</em>  This follows immediately from the previous lemma.</li>
<li>We reminded ourselves that if we are to find a continued fraction for the irrational number <img src='http://s0.wp.com/latex.php?latex=%5Ctheta&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;theta' title='&#92;theta' class='latex' />, then we must have <img src='http://s0.wp.com/latex.php?latex=a_0+%3D+%5Clfloor+%5Ctheta+%5Crfloor&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='a_0 = &#92;lfloor &#92;theta &#92;rfloor' title='a_0 = &#92;lfloor &#92;theta &#92;rfloor' class='latex' />, and <img src='http://s0.wp.com/latex.php?latex=%5Calpha_1+%3D+%5Cfrac%7B1%7D%7B%5Ctheta+-+a_0%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;alpha_1 = &#92;frac{1}{&#92;theta - a_0}' title='&#92;alpha_1 = &#92;frac{1}{&#92;theta - a_0}' class='latex' />, and <img src='http://s0.wp.com/latex.php?latex=a_i+%3D+%5Clfloor+%5Calpha_i+%5Crfloor&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='a_i = &#92;lfloor &#92;alpha_i &#92;rfloor' title='a_i = &#92;lfloor &#92;alpha_i &#92;rfloor' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=%5Calpha_%7Bi%2B1%7D+%3D+%5Cfrac%7B1%7D%7B%5Calpha_i+-+a_i%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;alpha_{i+1} = &#92;frac{1}{&#92;alpha_i - a_i}' title='&#92;alpha_{i+1} = &#92;frac{1}{&#92;alpha_i - a_i}' class='latex' /> for <img src='http://s0.wp.com/latex.php?latex=i+%5Cgeq+1&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='i &#92;geq 1' title='i &#92;geq 1' class='latex' />.</li>
<li>Proposition 61: <em>The convergents converge.  That is, if we define <img src='http://s0.wp.com/latex.php?latex=a_i&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='a_i' title='a_i' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=p_n&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='p_n' title='p_n' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=q_n&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='q_n' title='q_n' class='latex' /> as above, then the sequence <img src='http://s0.wp.com/latex.php?latex=%5Ba_0%5D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='[a_0]' title='[a_0]' class='latex' />,<em></em> <img src='http://s0.wp.com/latex.php?latex=%5Ba_0%2C+a_1%5D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='[a_0, a_1]' title='[a_0, a_1]' class='latex' />, <img src='http://s0.wp.com/latex.php?latex=%5Ba_0%2C+a_1%2C+a_2%5D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='[a_0, a_1, a_2]' title='[a_0, a_1, a_2]' class='latex' />, &#8230; converges to <img src='http://s0.wp.com/latex.php?latex=%5Ctheta&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;theta' title='&#92;theta' class='latex' />.</em>  We proved this by using Lemma 58 to show that <img src='http://s0.wp.com/latex.php?latex=%5Ctheta+%3D+%5Cfrac%7B%5Calpha_%7Bn%2B1%7D+p_n+%2B+p_%7Bn-1%7D%7D%7B%5Calpha_%7Bn%2B1%7D+q_n+%2B+q_%7Bn-1%7D%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;theta = &#92;frac{&#92;alpha_{n+1} p_n + p_{n-1}}{&#92;alpha_{n+1} q_n + q_{n-1}}' title='&#92;theta = &#92;frac{&#92;alpha_{n+1} p_n + p_{n-1}}{&#92;alpha_{n+1} q_n + q_{n-1}}' class='latex' />, and then computing <img src='http://s0.wp.com/latex.php?latex=%7C+%5Ctheta+-+%5Cfrac%7Bp_n%7D%7Bq_n%7D+%7C&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='| &#92;theta - &#92;frac{p_n}{q_n} |' title='| &#92;theta - &#92;frac{p_n}{q_n} |' class='latex' />.</li>
<li>Lemma 62: <em>We have <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7B1%7D%7Bq_%7Bn%2B2%7D%7D+%5Cleq+%7Cq_n+%5Ctheta+-+p_n+%7C+%5Cleq+%5Cfrac%7B1%7D%7Bq_%7Bn%2B1%7D%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;frac{1}{q_{n+2}} &#92;leq |q_n &#92;theta - p_n | &#92;leq &#92;frac{1}{q_{n+1}}' title='&#92;frac{1}{q_{n+2}} &#92;leq |q_n &#92;theta - p_n | &#92;leq &#92;frac{1}{q_{n+1}}' class='latex' /> for all <img src='http://s0.wp.com/latex.php?latex=n+%5Cgeq+0&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='n &#92;geq 0' title='n &#92;geq 0' class='latex' />, and so we also have <img src='http://s0.wp.com/latex.php?latex=%7C+q_n+%5Ctheta+-+p_n%7C+%5Cleq+%7C+q_%7Bn-1%7D+%5Ctheta+-+p+_%7Bn-1%7D%7C&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='| q_n &#92;theta - p_n| &#92;leq | q_{n-1} &#92;theta - p _{n-1}|' title='| q_n &#92;theta - p_n| &#92;leq | q_{n-1} &#92;theta - p _{n-1}|' class='latex' /> for <img src='http://s0.wp.com/latex.php?latex=n+%5Cgeq+1&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='n &#92;geq 1' title='n &#92;geq 1' class='latex' />.</em>  We used the expression we obtained for <img src='http://s0.wp.com/latex.php?latex=%7C+%5Ctheta+-+%5Cfrac%7Bp_n%7D%7Bq_n%7D%7C&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='| &#92;theta - &#92;frac{p_n}{q_n}|' title='| &#92;theta - &#92;frac{p_n}{q_n}|' class='latex' /> in the previous result, together with a couple of easy estimates using the recurrence for <img src='http://s0.wp.com/latex.php?latex=q_n&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='q_n' title='q_n' class='latex' />.</li>
</ul>
<h4>Further reading</h4>
<p>The usual selection.  Hardy and Wright (<em>An Introduction to the Theory of Numbers</em>) and Baker (<em>A concise introduction to the theory of numbers</em>) both discuss Diophantine approximation via continued fractions, and have some nice material going beyond the topics that we&#8217;ll see in lectures.</p>
<h4>Preparation for Lecture 20</h4>
<p>We&#8217;ve seen that continued fractions give a sequence of rational numbers that converge to a given real number (namely the convergents).  Next time we&#8217;ll consider these as rational approximations of that real number.  I suggest that you compute some convergents (for some examples that we haven&#8217;t seen in lectures), to see whether they give good approximations.  How do they compare with the rational approximations arising from truncating decimal expansions?</p>
<p>Next time we&#8217;ll see that in some sense the best rational approximations come from continued fractions.  You could usefully think about how we might formulate that result in a precise way (and, of course, how we might prove it).</p>
<p>We are then going to turn our attention to the Diophantine equation <img src='http://s0.wp.com/latex.php?latex=x%5E2+-+N+y%5E2+%3D+1&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='x^2 - N y^2 = 1' title='x^2 - N y^2 = 1' class='latex' /> (where <img src='http://s0.wp.com/latex.php?latex=N&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='N' title='N' class='latex' /> is a fixed integer that isn&#8217;t a square, and where we are looking for integer solutions <img src='http://s0.wp.com/latex.php?latex=x&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='x' title='x' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=y&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='y' title='y' class='latex' />).  Can you find some solutions when <img src='http://s0.wp.com/latex.php?latex=N+%3D+2&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='N = 2' title='N = 2' class='latex' /> or <img src='http://s0.wp.com/latex.php?latex=N+%3D+3&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='N = 3' title='N = 3' class='latex' />, for example?  It would be good to get a feeling for whether there are no solutions, some but only finitely many solutions, or infinitely many solutions, for different values of <img src='http://s0.wp.com/latex.php?latex=N&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='N' title='N' class='latex' />.</p>
<p>(And what happens to the equation <img src='http://s0.wp.com/latex.php?latex=x%5E2+-+N+y%5E2+%3D+1&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='x^2 - N y^2 = 1' title='x^2 - N y^2 = 1' class='latex' /> when <img src='http://s0.wp.com/latex.php?latex=N&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='N' title='N' class='latex' /> <em>is</em> a square?  Why have I ruled out that case above?)</p>
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		<title>Number Theory: Lecture 18</title>
		<link>http://theoremoftheweek.wordpress.com/2011/11/16/number-theory-lecture-18/</link>
		<comments>http://theoremoftheweek.wordpress.com/2011/11/16/number-theory-lecture-18/#comments</comments>
		<pubDate>Wed, 16 Nov 2011 12:36:13 +0000</pubDate>
		<dc:creator>theoremoftheweek</dc:creator>
				<category><![CDATA[Cambridge Maths Tripos]]></category>
		<category><![CDATA[II Number Theory]]></category>
		<category><![CDATA[Lecture]]></category>

		<guid isPermaLink="false">http://theoremoftheweek.wordpress.com/?p=1043</guid>
		<description><![CDATA[In which we start our study of Diophantine approximation and meet continued fractions. We concluded the proof of Bertrand&#8217;s postulate from last time. Proposition 56 (Dirichlet): Let be a real number and let be a natural number.  Then there is a rational with such that .  We saw that we could prove this quite easily [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=theoremoftheweek.wordpress.com&amp;blog=8730266&amp;post=1043&amp;subd=theoremoftheweek&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p><em>In which we start our study of <a title="MacTutor biography of Diophantus" href="http://www.gap-system.org/~history/Mathematicians/Diophantus.html">Diophantine</a> approximation and meet continued fractions.</em></p>
<p><span id="more-1043"></span></p>
<ul>
<li>We concluded the proof of <a title="Number Theory Lecture 17" href="http://theoremoftheweek.wordpress.com/2011/11/14/number-theory-lecture-17/">Bertrand&#8217;s postulate</a> from last time.</li>
<li><a title="Theorem 11: the pigeonhole principle" href="http://theoremoftheweek.wordpress.com/2009/10/25/theorem-11-the-pigeonhole-principle/">Proposition 56</a> (<a title="MacTutor biography of Dirichlet" href="http://www.gap-system.org/%7Ehistory/Mathematicians/Dirichlet.html">Dirichlet</a>): <em>Let <img src='http://s0.wp.com/latex.php?latex=%5Ctheta&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;theta' title='&#92;theta' class='latex' /> be a real number and let <img src='http://s0.wp.com/latex.php?latex=N&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='N' title='N' class='latex' /> be a natural number.  Then there is a rational <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7Ba%7D%7Bq%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;frac{a}{q}' title='&#92;frac{a}{q}' class='latex' /> with <img src='http://s0.wp.com/latex.php?latex=1+%5Cleq+q+%5Cleq+N&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='1 &#92;leq q &#92;leq N' title='1 &#92;leq q &#92;leq N' class='latex' /> such that <img src='http://s0.wp.com/latex.php?latex=%7C+%5Ctheta+-+%5Cfrac%7Ba%7D%7Bq%7D+%7C+%3C+%5Cfrac%7B1%7D%7BqN%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='| &#92;theta - &#92;frac{a}{q} | &lt; &#92;frac{1}{qN}' title='| &#92;theta - &#92;frac{a}{q} | &lt; &#92;frac{1}{qN}' class='latex' />.</em>  We saw that we could prove this quite easily using the pigeonhole principle.</li>
<li>Definition of <em>continued fractions</em> (finite and infinite), and <em>partial quotients.</em></li>
<li>Lemma 57: <em>There is a one-to-one correspondence between finite continued fractions and rational numbers.</em>  We saw the important point that the continued fraction of a rational number must terminate, and saw the link to <a title="Number Theory Lecture 1" href="http://theoremoftheweek.wordpress.com/2011/10/07/number-theory-lecture-1/">Euclid&#8217;s algorithm</a>.<em><br />
</em></li>
</ul>
<h4>Further reading</h4>
<p>Davenport (<em>The Higher Arithmetic</em>), Baker (<em>A concise introduction to the theory of numbers</em>), and Hardy and Wright (<em>An Introduction to the Theory of Numbers</em>) all have good sections on continued fractions, including material beyond what we&#8217;ll cover in lectures.</p>
<h4>Preparation for Lecture 19</h4>
<p>Our next job will be to think about infinite continued fractions.  Can you find a continued fraction for <img src='http://s0.wp.com/latex.php?latex=%5Csqrt%7B2%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;sqrt{2}' title='&#92;sqrt{2}' class='latex' />?  Is it unique?  If you truncate the continued fraction at some point, you get a finite continued fraction and so a rational number.  How does it compare with <img src='http://s0.wp.com/latex.php?latex=%5Csqrt%7B2%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;sqrt{2}' title='&#92;sqrt{2}' class='latex' />?  Investigating these truncated continued fractions before the next lecture would be very helpful.</p>
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		<title>Number Theory: Lecture 17</title>
		<link>http://theoremoftheweek.wordpress.com/2011/11/14/number-theory-lecture-17/</link>
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		<pubDate>Mon, 14 Nov 2011 12:14:53 +0000</pubDate>
		<dc:creator>theoremoftheweek</dc:creator>
				<category><![CDATA[Cambridge Maths Tripos]]></category>
		<category><![CDATA[II Number Theory]]></category>
		<category><![CDATA[Lecture]]></category>

		<guid isPermaLink="false">http://theoremoftheweek.wordpress.com/?p=1329</guid>
		<description><![CDATA[In which we gain some further insight into the distribution of the primes. Proposition 52 (Legendre&#8216;s formula): For , we have .  We saw that this follows nicely from the inclusion-exclusion principle. Lemma 53:  For any natural number , we have .  These are both easy bounds arising from the expansion of or from counting [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=theoremoftheweek.wordpress.com&amp;blog=8730266&amp;post=1329&amp;subd=theoremoftheweek&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p><em>In which we gain some further insight into the distribution of the primes.</em></p>
<p><span id="more-1329"></span></p>
<ul>
<li><img title="More..." src="https://theoremoftheweek.wordpress.com/wp-includes/js/tinymce/plugins/wordpress/img/trans.gif" alt="" />Proposition 52 (<a title="MacTutor biography of Legendre" href="http://www.gap-system.org/%7Ehistory/Mathematicians/Legendre.html">Legendre</a>&#8216;s formula): <em>For <img src='http://s0.wp.com/latex.php?latex=x+%5Cgeq+10&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='x &#92;geq 10' title='x &#92;geq 10' class='latex' />, we have <img src='http://s0.wp.com/latex.php?latex=%5Cpi%28x%29+%3D+%5Cpi%28%5Csqrt%7Bx%7D%29+-+1+%2B+%5Clfloor+x+%5Crfloor+-+%5Csum_%7Bp+%5Cleq+%5Csqrt%7Bx%7D%7D+%5Clfloor+%5Cfrac%7Bx%7D%7Bp%7D+%5Crfloor+%2B+%5Csum_%7Bp_1+%3C+p_2+%5Cleq+%5Csqrt%7Bx%7D%7D+%5Clfloor+%5Cfrac%7Bx%7D%7Bp_1+p_2%7D+%5Crfloor+-+%5Cdotsb&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;pi(x) = &#92;pi(&#92;sqrt{x}) - 1 + &#92;lfloor x &#92;rfloor - &#92;sum_{p &#92;leq &#92;sqrt{x}} &#92;lfloor &#92;frac{x}{p} &#92;rfloor + &#92;sum_{p_1 &lt; p_2 &#92;leq &#92;sqrt{x}} &#92;lfloor &#92;frac{x}{p_1 p_2} &#92;rfloor - &#92;dotsb' title='&#92;pi(x) = &#92;pi(&#92;sqrt{x}) - 1 + &#92;lfloor x &#92;rfloor - &#92;sum_{p &#92;leq &#92;sqrt{x}} &#92;lfloor &#92;frac{x}{p} &#92;rfloor + &#92;sum_{p_1 &lt; p_2 &#92;leq &#92;sqrt{x}} &#92;lfloor &#92;frac{x}{p_1 p_2} &#92;rfloor - &#92;dotsb' class='latex' />.</em>  We saw that this follows nicely from the <a title="Theorem 16: the inclusion-exclusion principle" href="http://theoremoftheweek.wordpress.com/2010/02/03/theorem-16-the-inclusion-exclusion-principle/">inclusion-exclusion principle</a>.</li>
<li>Lemma 53:  <em>For any natural number <img src='http://s0.wp.com/latex.php?latex=n&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='n' title='n' class='latex' />, we have <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7B2%5E%7B2n%7D%7D%7B2n%7D+%5Cleq+%5Cbinom%7B2n%7D%7Bn%7D+%3C+2%5E%7B2n%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;frac{2^{2n}}{2n} &#92;leq &#92;binom{2n}{n} &lt; 2^{2n}' title='&#92;frac{2^{2n}}{2n} &#92;leq &#92;binom{2n}{n} &lt; 2^{2n}' class='latex' />.</em>  These are both easy bounds arising from the expansion of <img src='http://s0.wp.com/latex.php?latex=%281+%2B+1%29%5E%7B2n%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='(1 + 1)^{2n}' title='(1 + 1)^{2n}' class='latex' /> or from counting subsets of <img src='http://s0.wp.com/latex.php?latex=%5C%7B1%2C+2%2C+%5Cdotsc%2C+2n+%5C%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;{1, 2, &#92;dotsc, 2n &#92;}' title='&#92;{1, 2, &#92;dotsc, 2n &#92;}' class='latex' />.<br />
Lemma 54: <em>For any <img src='http://s0.wp.com/latex.php?latex=x+%5Cgeq+1&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='x &#92;geq 1' title='x &#92;geq 1' class='latex' />, we have <img src='http://s0.wp.com/latex.php?latex=%5Cprod_%7Bp+%5Cleq+x%7D+p+%5Cleq+4%5Ex&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;prod_{p &#92;leq x} p &#92;leq 4^x' title='&#92;prod_{p &#92;leq x} p &#92;leq 4^x' class='latex' />.</em>  We proved this for natural numbers <img src='http://s0.wp.com/latex.php?latex=x&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='x' title='x' class='latex' /> using induction.</li>
<li>Theorem 55 (<a title="MacTutor biography of Bertrand" href="http://www.gap-system.org/%7Ehistory/Biographies/Bertrand.html">Bertrand</a>&#8216;s postulate): <em>For any natural number <img src='http://s0.wp.com/latex.php?latex=n&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='n' title='n' class='latex' />, there is a prime <img src='http://s0.wp.com/latex.php?latex=p&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='p' title='p' class='latex' /> with <img src='http://s0.wp.com/latex.php?latex=n+%3C+p+%5Cleq+2n&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='n &lt; p &#92;leq 2n' title='n &lt; p &#92;leq 2n' class='latex' />.</em>  Our strategy was to show that the product <img src='http://s0.wp.com/latex.php?latex=%5Cprod_%7Bn+%3C+p+%5Cleq+2n%7D+p&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;prod_{n &lt; p &#92;leq 2n} p' title='&#92;prod_{n &lt; p &#92;leq 2n} p' class='latex' /> is strictly bigger than 1.  We noticed that this product divides the binomial coefficient <img src='http://s0.wp.com/latex.php?latex=%5Cbinom%7B2n%7D%7Bn%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;binom{2n}{n}' title='&#92;binom{2n}{n}' class='latex' />, and found an upper bound for the remainder of the contribution.  Next time we&#8217;ll finish studying this upper bound in order to obtain the lower bound on <img src='http://s0.wp.com/latex.php?latex=%5Cprod_%7Bn+%3C+p+%5Cleq+2n%7Dp&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;prod_{n &lt; p &#92;leq 2n}p' title='&#92;prod_{n &lt; p &#92;leq 2n}p' class='latex' /> that we wanted.  In the meantime, I encourage you to try to finish the proof for yourself.</li>
</ul>
<h4>Further reading</h4>
<p>Erdős and Surányi (<em>Topics in the theory of numbers</em>) discuss Bertrand&#8217;s postulate and a number of other interesting results relating to the distribution of the primes.  There&#8217;s also a proof of Bertrand&#8217;s postulate in Hardy and Wright (<em>An Introduction to the Theory of Numbers</em>).</p>
<h4>Preparation for Lecture 18</h4>
<p>Of course, you should try to finish the proof of Bertrand&#8217;s postulate for yourself.</p>
<p>Then next time we&#8217;ll have another change of topic.  We&#8217;re going to think about approximating irrational numbers by rationals (Diophantine approximation).  The aim is to get a very good approximation by a rational with very small denominator.  How would you go about finding a good rational approximation to <img src='http://s0.wp.com/latex.php?latex=%5Csqrt%7B2%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;sqrt{2}' title='&#92;sqrt{2}' class='latex' /> or <img src='http://s0.wp.com/latex.php?latex=%5Cpi&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;pi' title='&#92;pi' class='latex' />, for example?  If you find a good approximation, can you be confident that it&#8217;s the best option?  (That is, could there be another rational with smaller denominator that gives a better approximation?)</p>
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		<title>Number Theory: Lecture 16</title>
		<link>http://theoremoftheweek.wordpress.com/2011/11/11/number-theory-lecture-16/</link>
		<comments>http://theoremoftheweek.wordpress.com/2011/11/11/number-theory-lecture-16/#comments</comments>
		<pubDate>Fri, 11 Nov 2011 21:18:15 +0000</pubDate>
		<dc:creator>theoremoftheweek</dc:creator>
				<category><![CDATA[Cambridge Maths Tripos]]></category>
		<category><![CDATA[II Number Theory]]></category>
		<category><![CDATA[Lecture]]></category>

		<guid isPermaLink="false">http://theoremoftheweek.wordpress.com/?p=1316</guid>
		<description><![CDATA[In which we encounter the Prime Number Theorem. Theorem 50 (Prime Number Theorem): We have as .  That is, as .  We saw some of the key ideas of the proof, but did not go into detail. Definition of the von Mangoldt function . Lemma 51: If then .  The left-hand side is the logarithmic [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=theoremoftheweek.wordpress.com&amp;blog=8730266&amp;post=1316&amp;subd=theoremoftheweek&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p><em>In which we encounter the Prime Number Theorem.</em></p>
<p><span id="more-1316"></span></p>
<ul>
<li><img title="More..." src="https://theoremoftheweek.wordpress.com/wp-includes/js/tinymce/plugins/wordpress/img/trans.gif" alt="" />Theorem 50 (Prime Number Theorem): <em>We have <img src='http://s0.wp.com/latex.php?latex=%5Cpi%28x%29+%5Csim+%5Cfrac%7Bx%7D%7B%5Clog+x%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;pi(x) &#92;sim &#92;frac{x}{&#92;log x}' title='&#92;pi(x) &#92;sim &#92;frac{x}{&#92;log x}' class='latex' /> as <img src='http://s0.wp.com/latex.php?latex=x+%5Cto+%5Cinfty&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='x &#92;to &#92;infty' title='x &#92;to &#92;infty' class='latex' />.  That is, <img src='http://s0.wp.com/latex.php?latex=%5Cpi%28x%29%2F%28x%2F%5Clog+x%29+%5Cto+1&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;pi(x)/(x/&#92;log x) &#92;to 1' title='&#92;pi(x)/(x/&#92;log x) &#92;to 1' class='latex' /> as <img src='http://s0.wp.com/latex.php?latex=x+%5Cto+%5Cinfty&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='x &#92;to &#92;infty' title='x &#92;to &#92;infty' class='latex' />.</em>  We saw some of the key ideas of the proof, but did not go into detail.</li>
<li>Definition of the <em>von Mangoldt function </em><img src='http://s0.wp.com/latex.php?latex=%5CLambda&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;Lambda' title='&#92;Lambda' class='latex' />.</li>
<li>Lemma 51: <em>If <img src='http://s0.wp.com/latex.php?latex=%5CRe%28s%29+%3E+1&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;Re(s) &gt; 1' title='&#92;Re(s) &gt; 1' class='latex' /> then <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7B%5Czeta%27%28s%29%7D%7B%5Czeta%28s%29%7D+%3D+-+%5Csum_%7Bn%3D1%7D%5E%7B%5Cinfty%7D+%5Cfrac%7B%5CLambda%28n%29%7D%7Bn%5Es%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;frac{&#92;zeta&#039;(s)}{&#92;zeta(s)} = - &#92;sum_{n=1}^{&#92;infty} &#92;frac{&#92;Lambda(n)}{n^s}' title='&#92;frac{&#92;zeta&#039;(s)}{&#92;zeta(s)} = - &#92;sum_{n=1}^{&#92;infty} &#92;frac{&#92;Lambda(n)}{n^s}' class='latex' />.</em>  The left-hand side is the logarithmic derivative of the zeta function.  We saw that we could obtain the right-hand side by taking the logarithm of the Euler product and then differentiating.</li>
<li>Definition of the <em>Dirichlet series</em> <img src='http://s0.wp.com/latex.php?latex=%5Csum_%7Bn%3D1%7D%5E%7B%5Cinfty%7D+%5Cfrac%7Ba_n%7D%7Bn%5Es%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;sum_{n=1}^{&#92;infty} &#92;frac{a_n}{n^s}' title='&#92;sum_{n=1}^{&#92;infty} &#92;frac{a_n}{n^s}' class='latex' /> corresponding to a sequence <img src='http://s0.wp.com/latex.php?latex=%28a_n%29&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='(a_n)' title='(a_n)' class='latex' />.</li>
</ul>
<p>I gave out the third examples sheet, which is now available on the <a title="Number Theory course page" href="http://www.dpmms.cam.ac.uk/~vrn20/NumberTheory2011.html">course page</a>.  I am grateful to the eagle-eyed student who spotted a typo before the end of the lecture: the first <img src='http://s0.wp.com/latex.php?latex=N&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='N' title='N' class='latex' /> in Q6(i) should of course have been an <img src='http://s0.wp.com/latex.php?latex=N%21&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='N!' title='N!' class='latex' />.  I have corrected this in the online version.  Apologies for any confusion this may have caused.</p>
<h4>Further reading</h4>
<p>The suggestions I made for the <a title="Number Theory lecture 15" href="http://theoremoftheweek.wordpress.com/2011/11/09/number-theory-lecture-15/">last lecture</a> are just as valid for this lecture.  There&#8217;s some nice material on the distribution of the primes in <em>Topics in the Theory of Numbers</em>, by <a title="MacTutor biography of Erdos" href="http://www.gap-system.org/%7Ehistory/Mathematicians/Erdos.html">Erdős</a> and Surányi.  There&#8217;s some discussion of an elementary proof of the Prime Number Theorem in <em>An Introduction to the Theory of Numbers</em> by Hardy and Wright (at least in the later editions &#8212; there was no known elementary proof when the first edition was written!).   Terry Tao has a nice <a title="Terry Tao blog post on the prime number theorem" href="http://terrytao.wordpress.com/2009/09/24/the-prime-number-theorem-in-arithmetic-progressions-and-dueling-conspiracies/">blog post</a> discussing a number of aspects of the distribution of prime numbers.</p>
<h4>Preparation for Lecture 17</h4>
<p>We&#8217;re going to move on to another formula for <img src='http://s0.wp.com/latex.php?latex=%5Cpi%28x%29&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;pi(x)' title='&#92;pi(x)' class='latex' />, the number of primes less than <img src='http://s0.wp.com/latex.php?latex=x&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='x' title='x' class='latex' />.  How would you compute the number of primes less than 100, or less than 1000 (without a computer, and without just listing all the primes!).  Can you generalise your ideas to find an expression for <img src='http://s0.wp.com/latex.php?latex=%5Cpi%28x%29&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;pi(x)' title='&#92;pi(x)' class='latex' /> (an exact expression, not an asymptotic formula)?</p>
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		<title>Number Theory: Lecture 15</title>
		<link>http://theoremoftheweek.wordpress.com/2011/11/09/number-theory-lecture-15/</link>
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		<pubDate>Wed, 09 Nov 2011 12:15:12 +0000</pubDate>
		<dc:creator>theoremoftheweek</dc:creator>
				<category><![CDATA[Cambridge Maths Tripos]]></category>
		<category><![CDATA[II Number Theory]]></category>
		<category><![CDATA[Lecture]]></category>

		<guid isPermaLink="false">http://theoremoftheweek.wordpress.com/?p=1303</guid>
		<description><![CDATA[In which we meet the Riemann zeta function and start to explore what it can tell us about prime numbers. Definition of the Riemann zeta function for . Lemma 47: If , then converges absolutely.  Moreover, for any the series converges uniformly for , and so is analytic on .  The important point to remember [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=theoremoftheweek.wordpress.com&amp;blog=8730266&amp;post=1303&amp;subd=theoremoftheweek&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p><em>In which we meet the Riemann zeta function and start to explore what it can tell us about prime numbers.</em></p>
<p><span id="more-1303"></span></p>
<ul>
<li><img title="More..." src="https://theoremoftheweek.wordpress.com/wp-includes/js/tinymce/plugins/wordpress/img/trans.gif" alt="" />Definition of the <em><a title="MacTutor biography of Riemann" href="http://www.gap-system.org/%7Ehistory/Mathematicians/Riemann.html">Riemann</a> zeta function</em> <img src='http://s0.wp.com/latex.php?latex=%5Czeta%28s%29+%3D+%5Csum_%7Bn%3D1%7D%5E%7B%5Cinfty%7D+%5Cfrac%7B1%7D%7Bn%5Es%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;zeta(s) = &#92;sum_{n=1}^{&#92;infty} &#92;frac{1}{n^s}' title='&#92;zeta(s) = &#92;sum_{n=1}^{&#92;infty} &#92;frac{1}{n^s}' class='latex' /> for <img src='http://s0.wp.com/latex.php?latex=%5CRe%28s%29+%3E+1&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;Re(s) &gt; 1' title='&#92;Re(s) &gt; 1' class='latex' />.</li>
<li>Lemma 47: <em>If <img src='http://s0.wp.com/latex.php?latex=%5CRe%28s%29+%3E+1&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;Re(s) &gt; 1' title='&#92;Re(s) &gt; 1' class='latex' />, then <img src='http://s0.wp.com/latex.php?latex=%5Csum_%7Bn%3D1%7D%5E%7B%5Cinfty%7D+%5Cfrac%7B1%7D%7Bn%5Es%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;sum_{n=1}^{&#92;infty} &#92;frac{1}{n^s}' title='&#92;sum_{n=1}^{&#92;infty} &#92;frac{1}{n^s}' class='latex' /> converges absolutely.  Moreover, for any <img src='http://s0.wp.com/latex.php?latex=%5Cdelta+%3E+0&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;delta &gt; 0' title='&#92;delta &gt; 0' class='latex' /> the series converges uniformly for <img src='http://s0.wp.com/latex.php?latex=%5CRe%28s%29+%5Cgeq+1+%2B+%5Cdelta&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;Re(s) &#92;geq 1 + &#92;delta' title='&#92;Re(s) &#92;geq 1 + &#92;delta' class='latex' />, and so is analytic on <img src='http://s0.wp.com/latex.php?latex=%5CRe%28s%29+%3E+1&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;Re(s) &gt; 1' title='&#92;Re(s) &gt; 1' class='latex' />.</em>  The important point to remember here is that <img src='http://s0.wp.com/latex.php?latex=s&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='s' title='s' class='latex' /> is complex.  Writing <img src='http://s0.wp.com/latex.php?latex=s+%3D+%5Csigma+%2B+it&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='s = &#92;sigma + it' title='s = &#92;sigma + it' class='latex' /> (as is standard, if bizarre), we have <img src='http://s0.wp.com/latex.php?latex=%7Cn%5E%7B-s%7D%7C+%3D+n%5E%7B-%5Csigma%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='|n^{-s}| = n^{-&#92;sigma}' title='|n^{-s}| = n^{-&#92;sigma}' class='latex' />.<em><br />
</em></li>
<li>Proposition 48 (Euler product for <img src='http://s0.wp.com/latex.php?latex=%5Czeta&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;zeta' title='&#92;zeta' class='latex' />): <em>If <img src='http://s0.wp.com/latex.php?latex=%5CRe%28s%29+%3E+1&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;Re(s) &gt; 1' title='&#92;Re(s) &gt; 1' class='latex' />, then <img src='http://s0.wp.com/latex.php?latex=%5Czeta%28s%29+%3D+%5Cprod_p+%281-p%5E%7B-s%7D%29%5E%7B-1%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;zeta(s) = &#92;prod_p (1-p^{-s})^{-1}' title='&#92;zeta(s) = &#92;prod_p (1-p^{-s})^{-1}' class='latex' />, where the product is over all primes <img src='http://s0.wp.com/latex.php?latex=p&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='p' title='p' class='latex' />.</em>  We proved this by considering the &#8216;partial product&#8217; <img src='http://s0.wp.com/latex.php?latex=%5Cprod_%7Bp+%5Cleq+N%7D+%281-p%5E%7B-s%7D%29%5E%7B-1%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;prod_{p &#92;leq N} (1-p^{-s})^{-1}' title='&#92;prod_{p &#92;leq N} (1-p^{-s})^{-1}' class='latex' />.  Note that this result essentially records the <a title="Theorem 13: the fundamental theorem of arithmetic" href="http://theoremoftheweek.wordpress.com/2009/11/21/theorem-13-the-fundamental-theorem-of-arithmetic/">fundamental theorem of arithmetic</a>.  This Euler product is crucial for linking the zeta function to the primes.</li>
<li>Lemma 49: <em>If <img src='http://s0.wp.com/latex.php?latex=%5CRe%28s%29+%3E+1&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;Re(s) &gt; 1' title='&#92;Re(s) &gt; 1' class='latex' />, then <img src='http://s0.wp.com/latex.php?latex=%5Czeta%28s%29+%5Cneq+0&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;zeta(s) &#92;neq 0' title='&#92;zeta(s) &#92;neq 0' class='latex' />.</em>  We proved this using the Euler product, being careful about the infinite product (we showed that for a suitable <img src='http://s0.wp.com/latex.php?latex=X&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='X' title='X' class='latex' />, we have <img src='http://s0.wp.com/latex.php?latex=%5Cprod_%7Bp+%3E+X%7D+%281-p%5E%7B-s%7D%29%5E%7B-1%7D+%3E+%5Cfrac%7B1%7D%7B2%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;prod_{p &gt; X} (1-p^{-s})^{-1} &gt; &#92;frac{1}{2}' title='&#92;prod_{p &gt; X} (1-p^{-s})^{-1} &gt; &#92;frac{1}{2}' class='latex' />, and could then check individual factors <img src='http://s0.wp.com/latex.php?latex=%281-p%5E%7B-s%7D%29%5E%7B-1%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='(1-p^{-s})^{-1}' title='(1-p^{-s})^{-1}' class='latex' /> for primes <img src='http://s0.wp.com/latex.php?latex=p+%5Cleq+X&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='p &#92;leq X' title='p &#92;leq X' class='latex' />.</li>
<li>We noted (without proof) some properties of <img src='http://s0.wp.com/latex.php?latex=%5Czeta&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;zeta' title='&#92;zeta' class='latex' />, such as the continuation to a meromorphic function on the complex plane, and the functional equation.  We saw the Riemann Hypothesis, which asserts that all the non-trivial zeros of <img src='http://s0.wp.com/latex.php?latex=%5Czeta&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;zeta' title='&#92;zeta' class='latex' /> lie on the line <img src='http://s0.wp.com/latex.php?latex=%5CRe%28s%29+%3D+%5Cfrac%7B1%7D%7B2%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;Re(s) = &#92;frac{1}{2}' title='&#92;Re(s) = &#92;frac{1}{2}' class='latex' />.</li>
<li>Definition of the <em>Möbius function</em> <img src='http://s0.wp.com/latex.php?latex=%5Cmu&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;mu' title='&#92;mu' class='latex' />.  Exercise: show that <img src='http://s0.wp.com/latex.php?latex=%5Cmu&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;mu' title='&#92;mu' class='latex' /> is a multiplicative function.</li>
<li>We noted (without proof) that the Riemann Hypothesis is equivalent to the bound <img src='http://s0.wp.com/latex.php?latex=%5Csum_%7Bn+%5Cleq+x%7D+%5Cmu%28n%29+%3D+O_%7B%5Cepsilon%7D%28x%5E%7B%5Cfrac%7B1%7D%7B2%7D+%2B+%5Cepsilon%7D%29&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;sum_{n &#92;leq x} &#92;mu(n) = O_{&#92;epsilon}(x^{&#92;frac{1}{2} + &#92;epsilon})' title='&#92;sum_{n &#92;leq x} &#92;mu(n) = O_{&#92;epsilon}(x^{&#92;frac{1}{2} + &#92;epsilon})' class='latex' />.</li>
</ul>
<h4>Further reading</h4>
<p>There are many books that give introductions to the Riemann zeta function.  Davenport&#8217;s <em>Multiplicative Number Theory</em> goes into more depth than some.  Ben Green has some online <a title="Ben Green Additive Number Theory lecture notes" href="http://www.dpmms.cam.ac.uk/~bjg23/ANT.html">lecture notes</a> from a Part III course a few years ago.  The book <em>Analytic Number Theory</em> by Iwaniec and Kowalski tells you more than you realised you wanted to know about the zeta function and much else besides.</p>
<h4>Preparation for Lecture 16</h4>
<p>What is the relationship between <img src='http://s0.wp.com/latex.php?latex=%5Cmu&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;mu' title='&#92;mu' class='latex' /> and <img src='http://s0.wp.com/latex.php?latex=%5Czeta&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;zeta' title='&#92;zeta' class='latex' />?  Hint: can you write <img src='http://s0.wp.com/latex.php?latex=%5Csum_%7Bn+%5Cgeq+1%7D+%5Cfrac%7B%5Cmu%28n%29%7D%7Bn%5Es%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;sum_{n &#92;geq 1} &#92;frac{&#92;mu(n)}{n^s}' title='&#92;sum_{n &#92;geq 1} &#92;frac{&#92;mu(n)}{n^s}' class='latex' /> in terms of <img src='http://s0.wp.com/latex.php?latex=%5Czeta&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;zeta' title='&#92;zeta' class='latex' />?</p>
<p>Can you find an expression for <img src='http://s0.wp.com/latex.php?latex=%5Cfrac%7B%5Czeta%27%28s%29%7D%7B%5Czeta%28s%29%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;frac{&#92;zeta&#039;(s)}{&#92;zeta(s)}' title='&#92;frac{&#92;zeta&#039;(s)}{&#92;zeta(s)}' class='latex' /> of the form <img src='http://s0.wp.com/latex.php?latex=%5Csum_%7Bn+%5Cgeq+1%7D+%5Cfrac%7Ba_n%7D%7Bn%5Es%7D&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='&#92;sum_{n &#92;geq 1} &#92;frac{a_n}{n^s}' title='&#92;sum_{n &#92;geq 1} &#92;frac{a_n}{n^s}' class='latex' />?  (This latter series is called the Dirichlet series for the sequence <img src='http://s0.wp.com/latex.php?latex=a_n&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='a_n' title='a_n' class='latex' />.)  The values of <img src='http://s0.wp.com/latex.php?latex=a_n&amp;bg=ffffff&amp;fg=333333&amp;s=0' alt='a_n' title='a_n' class='latex' /> will be important when we come to think about the Prime Number Theorem.</p>
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