In which we consider continuous functions, Goldilocks, porridge, and the intermediate value theorem.
- Lemma 16: Let
be a subset of
and let
be a point in
. Let
be a function from
to
. Suppose that if
is a sequence in
such that
as
, then
as
. Then
is continuous at
. We proved this by contradiction: we supposed that
is not continuous at
and built a sequence
such that
as
but
as
.
- Lemma 17: Let
and
be subsets of
. Let
and
be functions such that
for all
. Suppose that
is continuous at some
and that
is continuous at
. Then the composition
is continuous at
. We proved this using Lemmas 15 and 16. Exercise: prove it directly from the definition of continuity.
- Theorem 18: (Intermediate value theorem) Let
be a function that is continuous on
with
. Then there is some
in
such that
. We proved this using ‘zooming in’ or ‘interval bisection’ or ‘lion hunting’ — this was the strategy that we used in lectures to prove the Bolzano-Weierstrass theorem.
Understanding today’s lecture
- Can you prove Lemma 17 directly from the definition of continuity? This is a good exercise for developing familiarity with the definition.
- Give another proof of the intermediate value theorem along the following lines. Let
. Show that this set has a supremum, say
. Show that
, and that
. (
I’ll put a proofsorter activity on theThere is now a proofsorter activity on the course webpagelater this week, but I recommend trying to prove it yourself first.) - Show that every real polynomial of odd degree has at least one real root. Is the same true for polynomials of even degree?
Further reading
There’s a link to a blog post about the intermediate value theorem in the summary of today’s lecture. There are lots of books and websites where you can read about this theorem — please leave a comment below if you have any recommendations. There’s a link above to a recipe for porridge.
Preparation for Lecture 9
Here are some functions defined on subsets of the real line . For each function
, decide whether
is bounded, and if so whether
attains its bounds. (E.g. if
for all
, is there some value of
such that
?
,
.
,
.
,
.
,
if
and
.
Can you generalise your findings? Can you find any necessary or sufficient conditions for to be bounded and to attain its bounds?
February 4, 2013 at 5:53 pm
Hey, Vicky, you should have reserved the Goldilocks story for when we do the Bear Category Theorem. ;P
February 4, 2013 at 5:57 pm
Thanks for that! Here’s a link for those puzzled by the remark:
http://en.wikipedia.org/wiki/Baire_category_theorem
Who knew that so much of mathematics was related to fairy tales? Any more examples, anyone?
February 4, 2013 at 7:21 pm
It seems someone managed to link the Bolzano-Weierstrass Theorem with Red Riding Hood!
http://people.maths.ox.ac.uk/macdonald/errh/101_analysis_bedtime_stories_%28epsilon_red_riding_hood%29.pdf
Perhaps we should add our own story to the book!
February 4, 2013 at 9:02 pm
Wow!
February 5, 2013 at 6:12 am
I recommend a very good book called “A Companion to Analysis” by T. W. Korner. He makes analysis a very easy subject. Suitable for Analysis 1 and 2.
February 6, 2013 at 12:43 pm
[...] Expositions of interesting mathematical results « Analysis I: Lecture 8 [...]
February 25, 2013 at 12:27 pm
[...] function from to . We then carefully checked the remaining properties using these. We used the intermediate value theorem for (vi). We noted that (ii) and (vi) show that the function is a group isomorphism between the [...]